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Mathematics Governor’s Institute 2003
(Download as Microsoft Word documents: OPP, Worksheet, You Will Not Believe This)
Title of Project: Optimal Product Packaging (OPP) using Volume & Surface Area
Team Members: Tammy Baumann, James Blanchard, Michael Cutter, Bill Feeley,
Rodney Hart
Grade Level and/or Courses: 9th/10th grade Geometry
Concepts Used: Volume: Surface Area of 3 Dimensional Shapes, Metric Measurement,
Cost Analysis
Pa Standards Addressed:
2.2.11A; 2.3.8D; 2.3.11C; 2.4.11B & E; 2.5.11A, B, C, D;
2.9.8D; 2.9.11A, I
NCTM Standards Addressed:
Geometry #1 & 4, Measurement #2,
Data Analysis #3,
Problem Solving, Connections
Introduction/ Application: Volume and Surface Area of a cylinder is the topic of the classroom discussion. We will explore as a class how to minimize surface area given a specific volume. The students will already understand all of the volume and surface area formulas. Students will already understand how to construct three dimensional shapes.
Question: What is the
optimal shape, when the surface area is minimized and the
volume of 355 cm3 is
maintained?
Model: Various packaging formats for liquids.
Resources and Materials (estimated costs): Worksheets (Surface
Area and Volume, You will
not believe this), Cardstock, Tape, Scissors,
Rulers,
Compasses
Procedures & Activities:
Short demonstration of calculations of minimum surface area
with a given volume of 355 cc performed on
a cylinder. Class
will go through all discussion and
calculations for the cylinder.
Students will be put into groups and
given class time to
work on the worksheet.
Answers:
Cylinder; Surface Area = 277.9 cm2
Radius = 3.83 cm
Height = 7.72 cm
Rectangular Prism; Surface Area = 300.76 cm2
Length = 7.08 cm
Height = 7.08 cm
Width = 7.08 cm
Square Pyramid: Surface Area =331.09 cm2
Length/ Width = 9.08 cm
Height = 12.92 cm
Sphere: Surface Area = 242.46 cm2
Radius = 4.39 cm
Cone: Surface Area = 305.48 cm2
Radius = 4.94 cm
Height = 13.88 cm
** These answers are optimal and student answers may very.
Rubric:
POINTS DESCRIPTION
4 Arrives
at answers on worksheet with all work
shown. Completes models of all
geometric shapes.
3 Arrives
at answers on worksheet (may or may not
show
work). Attempts Geometric models.
2 Arrives
at answers with no work shown on
worksheet.
1 Produces
some solutions. Worksheet not complete
and
no models attempted.
0 Off task. No work on worksheet and no models.
Accommodations/Adaptations:
ESL: Place students in small groups, paired with a student fluent in both languages
Special Ed: Multiple choices for dimensions provided on
the worksheet.
Enrichment: Each group presents
conclusions using technology. Organize
data
and chart results.
***Note***:
This is an exploratory exercise in which students are developing solutions. They may not arrive at the “best possible” solutions that have been provided. It is hoped that all students will arrive at the conclusion that the sphere is the most cost effective.
***Extension***:
The next logical step would be to have students use the graphing calculator and arrive at the optimal dimensions that maintain the constant volume and minimize the surface area of each solid.
In a deeper extension, classes would attempt to derive equations which would provide all solutions; through graph analysis on their graphing instrument, they will extract the optimal answers. The following equations provide the solutions for the cylinder, square pyramid , and cone:
CYLINDER: Y = (710/X) + 2PX2 ; where Y is Surface Area and X is the radius
SQUARE PYRAMID: Y = X2 + 2X[(1134225/X4) + (1/4)X2]1/2 ; where Y is Surface Area and X is the length of one side of the square base
(This equation can be simplified; however, students are able to follow its derivation in this form.)
CONE: Y = Pr2 + Pr[r2 + (1065/Pr2)2]1/2 ; where Y is Surface Area and X is the radius
(This equation can be simplified; however, students are able to follow its derivation in this form.)
Other applications would be presentations using PowerPoint or other available media.
Home
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Grades Pre K-2
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6-8 Grades 9-12